5.0 background

Hi,

when I am finished with a doc I exit the doc and LO leaves me with a display containing tiles of my recent files. Up to my most recent dev version of 5.0 the background was a slightly off white colour with the files tiled on top of this. The background is now a dull grey colour which quite frankly looks awful.

Is there anywhere to change the background of the tiled view (ie. not application specific)?

Cheers

timllloyd wrote

Hi,

when I am finished with a doc I exit the doc and LO leaves me with a
display containing tiles of my recent files. Up to my most recent dev
version of 5.0 the background was a slightly off white colour with the
files tiled on top of this. The background is now a dull grey colour
which quite frankly looks awful.

Is there anywhere to change the background of the tiled view (ie. not
application specific)?

Cheers

That is the new Design & UX-advise approved color pallet for the StartCenter
at 5.0. Also new for the 5.0 release are Expert Configuration stanzas to
change those colors.

Tools -> Options -> Advanced: Expert Configuration button

Enter "StartCenter" in the search bar.

You'll want these stanzas, values are from RGB hex values converted to
decimal integer--reverse the process to convert RGB colors of your choice
and enter the decimal integer value (i.e. use MS calculator in Programmer
mode to convert).:

StartCenterThumbnailsHighlightColor (default 1450253 --> #16210d or
LibreOffice Gray2)
StartCenterThumbnailsBackgroundcolor (default 6701886 --> #66433e or
LibreOffice Gray7)

See tdf#90452
<https://bugs.documentfoundation.org/show_bug.cgi?id=90452#c62>

Stuart

thanks for the pointer Stuart but I still need a bit more help choosing a color scheme.

If I head over to Options->Libreoffice->Colors I can see the RGB values for colors. EG Gray2 detailed below (1450253) is shown as R:221, G:221, B:221. I don't see the tie in between the RGB numbers and the number I need to enter in options.

Thanks

Open a spreadsheet.
Enter the three decimal RGB values into A1,B1,C1

=HEX2DEC(DEC2HEX(A1;2)&DEC2HEX(B1;2)&DEC2HEX(C1;2))
returns 14540253 for 221,221,221

wonderful. Thanks Andreas, that has nailed it. I'll note this down and experiment